A jar contains 24 marbles some are green and others are blue.
Marbles in a jar probability.
A jar contains 4 black marbles and 3 red marbles.
Total number of marbles 23 4 27 marbles p green marble of green marbles of marbles total 4 27 0 148 so the probability is 4 27 which is about a 14 8 chance.
What is the probability that you pick 3 green no red 1 of each at least 1 blue marble if a jar contains 5 blue 3 green and 4 red marbles.
Pose questions to the children about each of the jars and the probability of picking certain colored marbles.
P getting a color other than red p 25 55 455 probability of this happening 3 times in a row is found by 455 455 455 094 example 2.
Place the possible card in front of the jar.
So the probability of getting a blue marble is 13 42.
Remember there is one less marble in the jar.
So the next time.
For example if the answer is 2 3 the response should be 0 67.
The total number of marbles in the second jar is 42 marbles and the total number of blue marbles in the jar is 13.
13 is a prime number and 42.
Finally multiply the probabilities and reduce to get 1 19.
If a marble is drawn at random from the jar the probability that it is green is 32.
At least 1 red a jar contains 30 red marbles 12 yellow marbles 8 green marbles and 5 blue marbles.
A draw the tree diagram for the experiment.
The chance is 2 in 5 but after taking one out the chances change.
Two marbles are drawn without replacement.
Find the probability of picking green 4 20 then find the probability of picking blue 5 19.
B find probabilities for p bb p br p rb p ww p at least one red p exactly one red.
If we got a red marble before then the chance of a blue marble next is 2 in 4.
You can arrange the marbles however you like but each marble must be in a jar.